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Post by DBCooper on Jul 22, 2004 22:30:45 GMT -5
Can someone please post the wind "C" values used in the wind formula for the .338 Lapua magnum. (out to 1500 yrds)
X100 ==, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
M118LR/SB, 15, 15, 15, 15, 15, 14, 13, 13, 12, 11
THANKS
DBCooper
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Lindy
New Member
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Post by Lindy on Jul 23, 2004 8:22:32 GMT -5
DB - If I wanted to know that, what I'd do is to feed the data on your load into a ballistics program, set the program up for a 1 mph full-value crosswind, and use the output to derive that value.
For example, with my load, my ATRAG software tells me to use .76 MOA of wind at 1000 for a 1 mph crosswind. To back out that constant, I use the formula: Constant = (wind speed X range in hundreds)/MOA.
So, 10 X 1 / .76 = 13.2
Thirteen is close enough.
Do that for every even hundred yard value, and there you go.
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Acehigh
New Member
"It never rains on the internet" ASC2 unknown
Posts: 3
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Post by Acehigh on Jul 23, 2004 8:27:31 GMT -5
Don't ya just luv engineers??? You're a freakin genius, Lindy! I coulda thought about that fer 3 days an not figured it out.
John
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Post by DBCooper on Jul 23, 2004 8:59:15 GMT -5
Lindy,
Could have done the math thing . . . if i would have taken the time to THINK about it for a minute or two.
Just thought someone had it handy . . ....
DBCooper
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Lindy
New Member
Posts: 6
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Post by Lindy on Jul 23, 2004 23:17:06 GMT -5
Well, I didn't have it handy - I had to write out the equation, and solve for the constant.
But any good engineer should be able to start with Force = mass times acceleration, but you can't push on a rope, and derive anything. ;D
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